天才衝衝衝 2011-09-03 郭靜

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23 thoughts on “天才衝衝衝 2011-09-03 郭靜

  1. 為甚麼這個莎莎會這麼爛…
    那個性鍾的又沒表現, 只會在笑或發呆>.<
    唉…好想艾麗絲跟小嫺..T^T

  2. 浩子說的很對啊 因為鳥沒有碰到地所以當然不會被電死 因為根據歐姆定律 V=IR 電阻越大電流就越小 電線的電阻小而小鳥的電阻大所以電流會通過電線 而通過小鳥的電流則小到連鳥都感覺不到 但如果碰到地面的話因為地面的電壓是0 所以電流就會通過小鳥流到地面 這樣小鳥就會被電死了

      • It’s about why birds won’t get electrified when they’re on the wire.  According to the Ohm’s Law V=IR, when you have larger resistant, you will have smaller current.  because birds have much greater resistant than the wire, the electric current will be larger when passing through the wire rather than birds that’s why birds won’t get electrified. However, if there’s something connect birds with the ground, then the electric current will pass through birds and into the ground.  That way birds will be electrified and die because ground has no voltage and the electric current goes from high voltage to low voltage.

        • Besides the resistance, if it is a big bird, the potential difference between two legs might be large enough to induce sufficient killer current. Connection to ground is an extreme example for large potential difference.

    • 其實可以很簡單的敘述:小鳥兩腿之間的電壓不足以形成“回路”,所以電不死。

      因此如果一個人手抓高壓電線纜懸空也是電不死的~ lol

    • 小鳥站電線上為什麼沒被電到?是因為牠兩隻腳是站同一條電線上。牠沒有兩隻腳是站不同一條電線,兩隻腳是站同一條電線上,所以才沒有被電到。

    • the latter part is right but the previous part is wrong. Nothing to do with resistance (R). It is only to do with electric potential (U). Since the bird is on the same level as the wire so it has the same electric potential as the wire. And current (I) will only pass through when there is a potential difference, so there is no current through the bird if it stays on the wire.

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